Non-commutative regular local rings of dimension 2: Part II
نویسندگان
چکیده
منابع مشابه
Dimension Sequences for Commutative Rings
Let JR be a commutative ring with identity of finite (Krull) dimension n0, and for each positive integer /c, let nk be the dimension of the polynomial ring R = R[XU . . . , Xk] in k indeterminates over R. The sequence {wjiio * Ud the dimension sequence for R, and the sequence {di}fLl9 where dt = nt — ni_1 for each i, is called the difference sequence for R. We are concerned with a determination...
متن کاملSome Properties of Non-commutative Regular Graded Rings
Introduction. Let A be a noetherian ring. When A is commutative (of finite Krull dimension), A is said to be Gorenstein if its injective dimension is finite. If A has finite global dimension, one says that A is regular. If A is arbitrary, these hypotheses are not sufficient to obtain similar results to those of the commutative case. To remedy this problem, M. Auslander has introduced a suppleme...
متن کاملThe Λ - Dimension of Commutative Arithmetic Rings
It is shown that every commutative arithmetic ring R has λ-dimension ≤ 3. An example of a commutative Kaplansky ring with λ-dimension 3 is given. Moreover, if R satisfies one of the following conditions, semi-local, semi-prime, self f p-injective, zero-Krull dimensional, CF or FSI then λ-dim(R) ≤ 2. It is also shown that every zero-Krull dimensional commu-tative arithmetic ring is a Kaplansky r...
متن کاملNon-commutative reduction rings
Reduction relations are means to express congruences on rings. In the special case of congruences induced by ideals in commutative polynomial rings, the powerful tool of Gröbner bases can be characterized by properties of reduction relations associated with ideal bases. Hence, reduction rings can be seen as rings with reduction relations associated to subsets of the ring such that every finitel...
متن کاملCommutative Regular Rings without Prime Model Extensions
It is known that the theory K of commutative regular rings with identity has a model completion K . We show that there exists a countable model of K which has no prime extension to a model of K'. If K and K ate theories in a first order language L, then K is said to be a model completion of K if K extends K, every model of K can be embedded in a model of K , and for any model A of K and models ...
متن کاملذخیره در منابع من
با ذخیره ی این منبع در منابع من، دسترسی به آن را برای استفاده های بعدی آسان تر کنید
ژورنال
عنوان ژورنال: Journal of Algebra
سال: 1988
ISSN: 0021-8693
DOI: 10.1016/0021-8693(88)90028-2